2x^2(3x^-4+2y^1/2)

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Solution for 2x^2(3x^-4+2y^1/2) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x^2*(3*x^-4+(2*y^1)/2) = 0

2*x^2*(3*x^-4+(2*y)/2) = 0

2*x^2*(3*x^-4+y) = 0

( 2*x^2 )

2*x^2 = 0 // : 2

x^2 = 0

x = 0

( 3*x^-4+y )

3*x^-4 = -y // : 3

x^-4 = -y/3

-4 < 0

1/(x^4) = -y/3 // * x^4

1 = x^4*(-y/3) // : -y/3

-3*y^-1 = x^4

x^4 = -3*y^-1 // ^ 1/4

abs(x) = (-3)^(1/4)*y^(-1/4)

x = (-3)^(1/4)*y^(-1/4) or x = -((-3)^(1/4)*y^(-1/4))

x in { 0} 

x in { (-3)^(1/4)*y^(-1/4), -((-3)^(1/4)*y^(-1/4)) }

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